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10210332113 = 50320298871
BaseRepresentation
bin10011000001001010…
…10100110111010001
3222100120112121112122
421200211110313101
5131402321111423
64405054504025
7511010251052
oct114045246721
928316477478
1010210332113
11436a514703
121b8b505015
13c69451547
146cc074729
153eb5a88c8
hex260954dd1

10210332113 has 4 divisors (see below), whose sum is σ = 10230631488. Its totient is φ = 10190032740.

The previous prime is 10210332091. The next prime is 10210332149. The reversal of 10210332113 is 31123301201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10210332113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10210332091 and 10210332100.

It is not an unprimeable number, because it can be changed into a prime (10210337113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10148933 + ... + 10149938.

It is an arithmetic number, because the mean of its divisors is an integer number (2557657872).

Almost surely, 210210332113 is an apocalyptic number.

It is an amenable number.

10210332113 is a deficient number, since it is larger than the sum of its proper divisors (20299375).

10210332113 is an equidigital number, since it uses as much as digits as its factorization.

10210332113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20299374.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 10210332113 its reverse (31123301201), we get a palindrome (41333633314).

The spelling of 10210332113 in words is "ten billion, two hundred ten million, three hundred thirty-two thousand, one hundred thirteen".

Divisors: 1 503 20298871 10210332113