Search a number
-
+
102110133113 is a prime number
BaseRepresentation
bin101111100011000111…
…1001111101101111001
3100202120020020012200222
41133012033033231321
53133110143224423
6114524142305425
710243245545042
oct1370617175571
9322506205628
10102110133113
113a33956536a
1217958588275
139823a37911
144d293c78c9
1529c96043c8
hex17c63cfb79

102110133113 has 2 divisors, whose sum is σ = 102110133114. Its totient is φ = 102110133112.

The previous prime is 102110133107. The next prime is 102110133133. The reversal of 102110133113 is 311331011201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 91102556224 + 11007576889 = 301832^2 + 104917^2 .

It is a cyclic number.

It is not a de Polignac number, because 102110133113 - 214 = 102110116729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 102110133091 and 102110133100.

It is not a weakly prime, because it can be changed into another prime (102110133133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51055066556 + 51055066557.

It is an arithmetic number, because the mean of its divisors is an integer number (51055066557).

Almost surely, 2102110133113 is an apocalyptic number.

It is an amenable number.

102110133113 is a deficient number, since it is larger than the sum of its proper divisors (1).

102110133113 is an equidigital number, since it uses as much as digits as its factorization.

102110133113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 102110133113 its reverse (311331011201), we get a palindrome (413441144314).

The spelling of 102110133113 in words is "one hundred two billion, one hundred ten million, one hundred thirty-three thousand, one hundred thirteen".