10211020120013 has 2 divisors, whose sum is σ = 10211020120014. Its totient is φ = 10211020120012.

The previous prime is 10211020119977. The next prime is 10211020120031. The reversal of 10211020120013 is 31002102011201.

10211020120013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (10211020120031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10210753712329 + 266407684 = 3195427^2 + 16322^2 .

It is an emirp because it is prime and its reverse (31002102011201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10211020120013 - 2¹⁴ = 10211020103629 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10211020120013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10211020120073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105510060006 + 5105510060007.

It is an arithmetic number, because the mean of its divisors is an integer number (5105510060007).

Almost surely, 2^{10211020120013} is an apocalyptic number.

It is an amenable number.

10211020120013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10211020120013 is an equidigital number, since it uses as much as digits as its factorization.

10211020120013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 10211020120013 its reverse (31002102011201), we get a palindrome (41213122131214).

The spelling of 10211020120013 in words is "ten trillion, two hundred eleven billion, twenty million, one hundred twenty thousand, thirteen".