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10211023113 = 33403674371
BaseRepresentation
bin10011000001001111…
…11101100100001001
3222100121211201102020
421200213331210021
5131403010214423
64405121355053
7511016156454
oct114047754411
928317751366
1010211023113
11436a946885
121b8b798a89
13c69633c15
146cc1b449b
153eb6934e3
hex2609fd909

10211023113 has 4 divisors (see below), whose sum is σ = 13614697488. Its totient is φ = 6807348740.

The previous prime is 10211023093. The next prime is 10211023127. The reversal of 10211023113 is 31132011201.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10211023113 - 212 = 10211019017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10211023092 and 10211023101.

It is not an unprimeable number, because it can be changed into a prime (10211023153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1701837183 + ... + 1701837188.

It is an arithmetic number, because the mean of its divisors is an integer number (3403674372).

Almost surely, 210211023113 is an apocalyptic number.

It is an amenable number.

10211023113 is a deficient number, since it is larger than the sum of its proper divisors (3403674375).

10211023113 is an equidigital number, since it uses as much as digits as its factorization.

10211023113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3403674374.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 10211023113 its reverse (31132011201), we get a palindrome (41343034314).

The spelling of 10211023113 in words is "ten billion, two hundred eleven million, twenty-three thousand, one hundred thirteen".

Divisors: 1 3 3403674371 10211023113