Base | Representation |
---|---|
bin | 11101101101111101110… |
… | …01111100111111001111 |
3 | 10121121122220211020101201 |
4 | 32312332321330333033 |
5 | 113212213142042312 |
6 | 2101031433250331 |
7 | 133526026513453 |
oct | 16667671747717 |
9 | 3547586736351 |
10 | 1021110112207 |
11 | 364061046719 |
12 | 145a938639a7 |
13 | 753a0954ab3 |
14 | 375c9d40663 |
15 | 1b864bb4557 |
hex | edbee7cfcf |
1021110112207 has 2 divisors, whose sum is σ = 1021110112208. Its totient is φ = 1021110112206.
The previous prime is 1021110112193. The next prime is 1021110112247. The reversal of 1021110112207 is 7022110111201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1021110112207 - 27 = 1021110112079 is a prime.
It is a super-2 number, since 2×10211101122072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1021110112247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510555056103 + 510555056104.
It is an arithmetic number, because the mean of its divisors is an integer number (510555056104).
Almost surely, 21021110112207 is an apocalyptic number.
1021110112207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021110112207 is an equidigital number, since it uses as much as digits as its factorization.
1021110112207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 1021110112207 its reverse (7022110111201), we get a palindrome (8043220223408).
The spelling of 1021110112207 in words is "one trillion, twenty-one billion, one hundred ten million, one hundred twelve thousand, two hundred seven".
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