Base | Representation |
---|---|
bin | 10111001101111010010011… |
… | …001000100110010100001011 |
3 | 111101112201101121202112020201 |
4 | 113031322103020212110023 |
5 | 101340441332333444242 |
6 | 1001101053325033031 |
7 | 30336164201444101 |
oct | 2715722310462413 |
9 | 441481347675221 |
10 | 102111020999947 |
11 | 2a59904a364483 |
12 | b5519723b5777 |
13 | 44c904958799b |
14 | 1b302b22dbc71 |
15 | bc121e3234b7 |
hex | 5cde9322650b |
102111020999947 has 2 divisors, whose sum is σ = 102111020999948. Its totient is φ = 102111020999946.
The previous prime is 102111020999941. The next prime is 102111021000049. The reversal of 102111020999947 is 749999020111201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 102111020999947 - 235 = 102076661261579 is a prime.
It is not a weakly prime, because it can be changed into another prime (102111020999941) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51055510499973 + 51055510499974.
It is an arithmetic number, because the mean of its divisors is an integer number (51055510499974).
Almost surely, 2102111020999947 is an apocalyptic number.
102111020999947 is a deficient number, since it is larger than the sum of its proper divisors (1).
102111020999947 is an equidigital number, since it uses as much as digits as its factorization.
102111020999947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 734832, while the sum is 55.
The spelling of 102111020999947 in words is "one hundred two trillion, one hundred eleven billion, twenty million, nine hundred ninety-nine thousand, nine hundred forty-seven".
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