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10211131300130 = 254124905198293
BaseRepresentation
bin1001010010010111011011…
…0110101001100100100010
31100011011201022000120110222
42110211312312221210202
52314244344103101010
633414532353323042
72102505231651335
oct224456666514442
940134638016428
1010211131300130
113287575462812
12118ab9b266482
13590ba0654507
142743156dc61c
1512a935740355
hex94976da9922

10211131300130 has 16 divisors (see below), whose sum is σ = 18828329910264. Its totient is φ = 3984831726720.

The previous prime is 10211131300093. The next prime is 10211131300141. The reversal of 10211131300130 is 3100313111201.

It can be written as a sum of positive squares in 4 ways, for example, as 2073810245329 + 8137321054801 = 1440073^2 + 2852599^2 .

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10211131300099 and 10211131300108.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12452598737 + ... + 12452599556.

Almost surely, 210211131300130 is an apocalyptic number.

10211131300130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

10211131300130 is a deficient number, since it is larger than the sum of its proper divisors (8617198610134).

10211131300130 is a wasteful number, since it uses less digits than its factorization.

10211131300130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24905198341.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10211131300130 its reverse (3100313111201), we get a palindrome (13311444411331).

The spelling of 10211131300130 in words is "ten trillion, two hundred eleven billion, one hundred thirty-one million, three hundred thousand, one hundred thirty".

Divisors: 1 2 5 10 41 82 205 410 24905198293 49810396586 124525991465 249051982930 1021113130013 2042226260026 5105565650065 10211131300130