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1021125133 = 7145875019
BaseRepresentation
bin111100110111010…
…010001000001101
32122011102112100101
4330313102020031
54042402001013
6245154131101
734206264130
oct7467221015
92564375311
101021125133
11484442476
12245b80a91
13133725772
149988a217
155e9a58dd
hex3cdd220d

1021125133 has 4 divisors (see below), whose sum is σ = 1167000160. Its totient is φ = 875250108.

The previous prime is 1021125121. The next prime is 1021125137. The reversal of 1021125133 is 3315211201.

1021125133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3315211201 = 5603959159.

It is a cyclic number.

It is not a de Polignac number, because 1021125133 - 25 = 1021125101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1021125133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1021125137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72937503 + ... + 72937516.

It is an arithmetic number, because the mean of its divisors is an integer number (291750040).

Almost surely, 21021125133 is an apocalyptic number.

It is an amenable number.

1021125133 is a deficient number, since it is larger than the sum of its proper divisors (145875027).

1021125133 is an equidigital number, since it uses as much as digits as its factorization.

1021125133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 145875026.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 1021125133 is about 31955.0486308502. The cubic root of 1021125133 is about 1006.9926991822.

Adding to 1021125133 its reverse (3315211201), we get a palindrome (4336336334).

It can be divided in two parts, 10211 and 25133, that added together give a square (35344 = 1882).

The spelling of 1021125133 in words is "one billion, twenty-one million, one hundred twenty-five thousand, one hundred thirty-three".

Divisors: 1 7 145875019 1021125133