Base | Representation |
---|---|
bin | 10011000001010010… |
… | …00100001001101001 |
3 | 222100122101102000101 |
4 | 21200221010021221 |
5 | 131403043442413 |
6 | 4405131505401 |
7 | 511021502413 |
oct | 114051041151 |
9 | 28318342011 |
10 | 10211312233 |
11 | 4370024021 |
12 | 1b8b8b8261 |
13 | c697056b5 |
14 | 6cc24b9b3 |
15 | 3eb6ededd |
hex | 260a44269 |
10211312233 has 4 divisors (see below), whose sum is σ = 10213251840. Its totient is φ = 10209372628.
The previous prime is 10211312227. The next prime is 10211312263. The reversal of 10211312233 is 33221311201.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33221311201 = 13 ⋅2555485477.
It is a cyclic number.
It is not a de Polignac number, because 10211312233 - 229 = 9674441321 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 10211312233.
It is not an unprimeable number, because it can be changed into a prime (10211312203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 961885 + ... + 972442.
It is an arithmetic number, because the mean of its divisors is an integer number (2553312960).
Almost surely, 210211312233 is an apocalyptic number.
It is an amenable number.
10211312233 is a deficient number, since it is larger than the sum of its proper divisors (1939607).
10211312233 is an equidigital number, since it uses as much as digits as its factorization.
10211312233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1939606.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 10211312233 its reverse (33221311201), we get a palindrome (43432623434).
The spelling of 10211312233 in words is "ten billion, two hundred eleven million, three hundred twelve thousand, two hundred thirty-three".
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