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102113130040202 = 2411245282073661
BaseRepresentation
bin10111001101111100010000…
…110101111100101110001010
3111101112220211121021212120202
4113031330100311330232022
5101341010142242241302
61001102042505052202
730336300361132361
oct2715742065745612
9441486747255522
10102113130040202
112a599a31907656
12b552260787062
1344c92c44bc5b8
141b3043245c7d8
15bc12e4574202
hex5cdf10d7cb8a

102113130040202 has 8 divisors (see below), whose sum is σ = 156905541281412. Its totient is φ = 49811282946400.

The previous prime is 102113130040151. The next prime is 102113130040309. The reversal of 102113130040202 is 202040031311201.

It can be written as a sum of positive squares in 2 ways, for example, as 77313138398521 + 24799991641681 = 8792789^2 + 4979959^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1021131300402022 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 622641036749 + ... + 622641036912.

Almost surely, 2102113130040202 is an apocalyptic number.

102113130040202 is a deficient number, since it is larger than the sum of its proper divisors (54792411241210).

102113130040202 is a wasteful number, since it uses less digits than its factorization.

102113130040202 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1245282073704.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 102113130040202 its reverse (202040031311201), we get a palindrome (304153161351403).

The spelling of 102113130040202 in words is "one hundred two trillion, one hundred thirteen billion, one hundred thirty million, forty thousand, two hundred two".

Divisors: 1 2 41 82 1245282073661 2490564147322 51056565020101 102113130040202