Search a number
-
+
102113132131 = 23181201712161
BaseRepresentation
bin101111100011001101…
…0101011111001100011
3100202120102212120120201
41133012122223321203
53133111430212011
6114524330450031
710243313205403
oct1370632537143
9322512776521
10102113132131
113a34022359a
1217959593917
13982454799a
144d29968803
1529c99e7cc1
hex17c66abe63

102113132131 has 16 divisors (see below), whose sum is σ = 107203457088. Its totient is φ = 97077657600.

The previous prime is 102113132119. The next prime is 102113132167. The reversal of 102113132131 is 131231311201.

It is a cyclic number.

It is not a de Polignac number, because 102113132131 - 27 = 102113132003 is a prime.

It is a super-2 number, since 2×1021131321312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 102113132099 and 102113132108.

It is not an unprimeable number, because it can be changed into a prime (102113132101) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8390691 + ... + 8402851.

It is an arithmetic number, because the mean of its divisors is an integer number (6700216068).

Almost surely, 2102113132131 is an apocalyptic number.

102113132131 is a deficient number, since it is larger than the sum of its proper divisors (5090324957).

102113132131 is a wasteful number, since it uses less digits than its factorization.

102113132131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14382.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 102113132131 its reverse (131231311201), we get a palindrome (233344443332).

The spelling of 102113132131 in words is "one hundred two billion, one hundred thirteen million, one hundred thirty-two thousand, one hundred thirty-one".

Divisors: 1 23 181 2017 4163 12161 46391 279703 365077 2201141 8396771 24528737 50626243 564160951 4439701397 102113132131