Base | Representation |
---|---|
bin | 101111100011001101… |
… | …0101011111010000111 |
3 | 100202120102212120122001 |
4 | 1133012122223322013 |
5 | 3133111430212132 |
6 | 114524330450131 |
7 | 10243313205454 |
oct | 1370632537207 |
9 | 322512776561 |
10 | 102113132167 |
11 | 3a340223622 |
12 | 17959593947 |
13 | 98245479c7 |
14 | 4d2996882b |
15 | 29c99e7ce7 |
hex | 17c66abe87 |
102113132167 has 2 divisors, whose sum is σ = 102113132168. Its totient is φ = 102113132166.
The previous prime is 102113132119. The next prime is 102113132227. The reversal of 102113132167 is 761231311201.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-102113132167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102113132767) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51056566083 + 51056566084.
It is an arithmetic number, because the mean of its divisors is an integer number (51056566084).
Almost surely, 2102113132167 is an apocalyptic number.
102113132167 is a deficient number, since it is larger than the sum of its proper divisors (1).
102113132167 is an equidigital number, since it uses as much as digits as its factorization.
102113132167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 102113132167 its reverse (761231311201), we get a palindrome (863344443368).
The spelling of 102113132167 in words is "one hundred two billion, one hundred thirteen million, one hundred thirty-two thousand, one hundred sixty-seven".
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