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102113301 = 334037767
BaseRepresentation
bin1100001011000…
…10000000010101
321010010220010010
412011202000111
5202120111201
614044350433
72346643263
oct605420025
9233126103
10102113301
1152705264
122a245419
1318203694
14d7c1433
158e70bd6
hex6162015

102113301 has 4 divisors (see below), whose sum is σ = 136151072. Its totient is φ = 68075532.

The previous prime is 102113299. The next prime is 102113311. The reversal of 102113301 is 103311201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 102113301 - 21 = 102113299 is a prime.

It is a super-2 number, since 2×1021133012 = 20854252482233202, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102113311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17018881 + ... + 17018886.

It is an arithmetic number, because the mean of its divisors is an integer number (34037768).

Almost surely, 2102113301 is an apocalyptic number.

It is an amenable number.

102113301 is a deficient number, since it is larger than the sum of its proper divisors (34037771).

102113301 is an equidigital number, since it uses as much as digits as its factorization.

102113301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34037770.

The product of its (nonzero) digits is 18, while the sum is 12.

The square root of 102113301 is about 10105.1126168885. The cubic root of 102113301 is about 467.4058086615.

Adding to 102113301 its reverse (103311201), we get a palindrome (205424502).

The spelling of 102113301 in words is "one hundred two million, one hundred thirteen thousand, three hundred one".

Divisors: 1 3 34037767 102113301