Base | Representation |
---|---|
bin | 1001010010011010101010… |
… | …1000100100011101010011 |
3 | 1100011020221211200100011001 |
4 | 2110212222220210131103 |
5 | 2314303134001240103 |
6 | 33415154505202431 |
7 | 2102535610666222 |
oct | 224465250443523 |
9 | 40136854610131 |
10 | 10212000024403 |
11 | 3287980873161 |
12 | 118b1a2190417 |
13 | 590cab61a348 |
14 | 274398c36cb9 |
15 | 12a986b4001d |
hex | 949aaa24753 |
10212000024403 has 4 divisors (see below), whose sum is σ = 10656000025488. Its totient is φ = 9768000023320.
The previous prime is 10212000024377. The next prime is 10212000024463. The reversal of 10212000024403 is 30442000021201.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10212000024403 - 25 = 10212000024371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10212000024463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222000000508 + ... + 222000000553.
It is an arithmetic number, because the mean of its divisors is an integer number (2664000006372).
Almost surely, 210212000024403 is an apocalyptic number.
10212000024403 is a deficient number, since it is larger than the sum of its proper divisors (444000001085).
10212000024403 is an equidigital number, since it uses as much as digits as its factorization.
10212000024403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 444000001084.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 10212000024403 its reverse (30442000021201), we get a palindrome (40654000045604).
The spelling of 10212000024403 in words is "ten trillion, two hundred twelve billion, twenty-four thousand, four hundred three".
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