Base | Representation |
---|---|
bin | 101111100011011010… |
… | …0111011100101100011 |
3 | 100202120220211010011112 |
4 | 1133012310323211203 |
5 | 3133120210342011 |
6 | 114525134133535 |
7 | 10243425531614 |
oct | 1370664734543 |
9 | 322526733145 |
10 | 102120012131 |
11 | 3a3440a2645 |
12 | 1795b9512ab |
13 | 9825ab63a7 |
14 | 4d2a839c0b |
15 | 29ca40658b |
hex | 17c6d3b963 |
102120012131 has 2 divisors, whose sum is σ = 102120012132. Its totient is φ = 102120012130.
The previous prime is 102120012097. The next prime is 102120012133. The reversal of 102120012131 is 131210021201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 102120012131 - 218 = 102119749987 is a prime.
It is a super-2 number, since 2×1021200121312 (a number of 23 digits) contains 22 as substring.
Together with 102120012133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (102120012133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51060006065 + 51060006066.
It is an arithmetic number, because the mean of its divisors is an integer number (51060006066).
Almost surely, 2102120012131 is an apocalyptic number.
102120012131 is a deficient number, since it is larger than the sum of its proper divisors (1).
102120012131 is an equidigital number, since it uses as much as digits as its factorization.
102120012131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 102120012131 its reverse (131210021201), we get a palindrome (233330033332).
The spelling of 102120012131 in words is "one hundred two billion, one hundred twenty million, twelve thousand, one hundred thirty-one".
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