Base | Representation |
---|---|
bin | 11101101110001001101… |
… | …11000010011001010111 |
3 | 10121121220212210122002021 |
4 | 32313010313002121113 |
5 | 113212414230324343 |
6 | 2101045402354011 |
7 | 133531351605313 |
oct | 16670467023127 |
9 | 3547825718067 |
10 | 1021210011223 |
11 | 364102479296 |
12 | 145b011bb907 |
13 | 753b856163c |
14 | 375d9306b43 |
15 | 1b86d8490ed |
hex | edc4dc2657 |
1021210011223 has 2 divisors, whose sum is σ = 1021210011224. Its totient is φ = 1021210011222.
The previous prime is 1021210011191. The next prime is 1021210011253. The reversal of 1021210011223 is 3221100121201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1021210011223 - 25 = 1021210011191 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1021210011197 and 1021210011206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1021210011253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510605005611 + 510605005612.
It is an arithmetic number, because the mean of its divisors is an integer number (510605005612).
Almost surely, 21021210011223 is an apocalyptic number.
1021210011223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021210011223 is an equidigital number, since it uses as much as digits as its factorization.
1021210011223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1021210011223 its reverse (3221100121201), we get a palindrome (4242310132424).
The spelling of 1021210011223 in words is "one trillion, twenty-one billion, two hundred ten million, eleven thousand, two hundred twenty-three".
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