Base | Representation |
---|---|
bin | 1001010010011011000101… |
… | …0101101000010100101011 |
3 | 1100011021020200022200200022 |
4 | 2110212301111220110223 |
5 | 2314303401300000021 |
6 | 33415214004031055 |
7 | 2102541445011362 |
oct | 224466125502453 |
9 | 40137220280608 |
10 | 10212112500011 |
11 | 3287a29305804 |
12 | 118b21399248b |
13 | 590cc8a0b466 |
14 | 2743a9b547d9 |
15 | 12a99195b1ab |
hex | 949b156852b |
10212112500011 has 2 divisors, whose sum is σ = 10212112500012. Its totient is φ = 10212112500010.
The previous prime is 10212112499993. The next prime is 10212112500047. The reversal of 10212112500011 is 11000521121201.
It is a weak prime.
It is an emirp because it is prime and its reverse (11000521121201) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10212112500011 is a prime.
It is a super-3 number, since 3×102121125000113 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (10212112520011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106056250005 + 5106056250006.
It is an arithmetic number, because the mean of its divisors is an integer number (5106056250006).
Almost surely, 210212112500011 is an apocalyptic number.
10212112500011 is a deficient number, since it is larger than the sum of its proper divisors (1).
10212112500011 is an equidigital number, since it uses as much as digits as its factorization.
10212112500011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 10212112500011 its reverse (11000521121201), we get a palindrome (21212633621212).
The spelling of 10212112500011 in words is "ten trillion, two hundred twelve billion, one hundred twelve million, five hundred thousand, eleven".
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