Base | Representation |
---|---|
bin | 11101101110001010111… |
… | …01100100011101000001 |
3 | 10121121221120210211000021 |
4 | 32313011131210131001 |
5 | 113212424322042233 |
6 | 2101050403053441 |
7 | 133531533505231 |
oct | 16670535443501 |
9 | 3547846724007 |
10 | 1021220112193 |
11 | 3641081482a6 |
12 | 145b04671281 |
13 | 753ba68a148 |
14 | 375da7b5cc1 |
15 | 1b86e691e2d |
hex | edc5764741 |
1021220112193 has 2 divisors, whose sum is σ = 1021220112194. Its totient is φ = 1021220112192.
The previous prime is 1021220112191. The next prime is 1021220112229. The reversal of 1021220112193 is 3912110221201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 818892875329 + 202327236864 = 904927^2 + 449808^2 .
It is a cyclic number.
It is not a de Polignac number, because 1021220112193 - 21 = 1021220112191 is a prime.
Together with 1021220112191, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1021220112191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510610056096 + 510610056097.
It is an arithmetic number, because the mean of its divisors is an integer number (510610056097).
Almost surely, 21021220112193 is an apocalyptic number.
It is an amenable number.
1021220112193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021220112193 is an equidigital number, since it uses as much as digits as its factorization.
1021220112193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 25.
Adding to 1021220112193 its reverse (3912110221201), we get a palindrome (4933330333394).
The spelling of 1021220112193 in words is "one trillion, twenty-one billion, two hundred twenty million, one hundred twelve thousand, one hundred ninety-three".
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