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102122101019993 is a prime number
BaseRepresentation
bin10111001110000100100111…
…100011100001010101011001
3111101120202222210202212100112
4113032010213203201111121
5101341132030330114433
61001110125012214105
730340035602165405
oct2716044743412531
9441522883685315
10102122101019993
112a5a281578753a
12b553b4500a335
1344ca0c3c4b872
141b30a43a7c105
15bc166be1c348
hex5ce1278e1559

102122101019993 has 2 divisors, whose sum is σ = 102122101019994. Its totient is φ = 102122101019992.

The previous prime is 102122101019921. The next prime is 102122101020089. The reversal of 102122101019993 is 399910101221201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 56363261957209 + 45758839062784 = 7507547^2 + 6764528^2 .

It is a cyclic number.

It is not a de Polignac number, because 102122101019993 - 240 = 101022589392217 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 102122101019993.

It is not a weakly prime, because it can be changed into another prime (102122101069993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51061050509996 + 51061050509997.

It is an arithmetic number, because the mean of its divisors is an integer number (51061050509997).

Almost surely, 2102122101019993 is an apocalyptic number.

It is an amenable number.

102122101019993 is a deficient number, since it is larger than the sum of its proper divisors (1).

102122101019993 is an equidigital number, since it uses as much as digits as its factorization.

102122101019993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17496, while the sum is 41.

The spelling of 102122101019993 in words is "one hundred two trillion, one hundred twenty-two billion, one hundred one million, nineteen thousand, nine hundred ninety-three".