10212313124041 has 4 divisors (see below), whose sum is σ = 11671214998912. Its totient is φ = 8753411249172.

The previous prime is 10212313124033. The next prime is 10212313124063. The reversal of 10212313124041 is 14042131321201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10212313124041 - 2³ = 10212313124033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10212313123997 and 10212313124015.

It is not an unprimeable number, because it can be changed into a prime (10212313124641) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 729450937425 + ... + 729450937438.

It is an arithmetic number, because the mean of its divisors is an integer number (2917803749728).

Almost surely, 2^{10212313124041} is an apocalyptic number.

It is an amenable number.

10212313124041 is a deficient number, since it is larger than the sum of its proper divisors (1458901874871).

10212313124041 is an equidigital number, since it uses as much as digits as its factorization.

10212313124041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1458901874870.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 10212313124041 its reverse (14042131321201), we get a palindrome (24254444445242).

The spelling of 10212313124041 in words is "ten trillion, two hundred twelve billion, three hundred thirteen million, one hundred twenty-four thousand, forty-one".