Base | Representation |
---|---|
bin | 11101101110001100011… |
… | …10101110111010110001 |
3 | 10121121222111001120220122 |
4 | 32313012032232322301 |
5 | 113212441122000423 |
6 | 2101051543220025 |
7 | 133532051163314 |
oct | 16670616567261 |
9 | 3547874046818 |
10 | 1021233000113 |
11 | 364114450177 |
12 | 145b08a47615 |
13 | 753c0250331 |
14 | 375dc3ac97b |
15 | 1b87088a8c8 |
hex | edc63aeeb1 |
1021233000113 has 2 divisors, whose sum is σ = 1021233000114. Its totient is φ = 1021233000112.
The previous prime is 1021233000107. The next prime is 1021233000133. The reversal of 1021233000113 is 3110003321201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 916323733504 + 104909266609 = 957248^2 + 323897^2 .
It is a cyclic number.
It is not a de Polignac number, because 1021233000113 - 26 = 1021233000049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1021233000091 and 1021233000100.
It is not a weakly prime, because it can be changed into another prime (1021233000133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510616500056 + 510616500057.
It is an arithmetic number, because the mean of its divisors is an integer number (510616500057).
Almost surely, 21021233000113 is an apocalyptic number.
It is an amenable number.
1021233000113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021233000113 is an equidigital number, since it uses as much as digits as its factorization.
1021233000113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 1021233000113 its reverse (3110003321201), we get a palindrome (4131236321314).
The spelling of 1021233000113 in words is "one trillion, twenty-one billion, two hundred thirty-three million, one hundred thirteen", and thus it is an aban number.
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