Base | Representation |
---|---|
bin | 1001010010011100101011… |
… | …0110000001110110000011 |
3 | 1100011022100111112110102110 |
4 | 2110213022312001312003 |
5 | 2314310240322023210 |
6 | 33415324251550403 |
7 | 2102555162213031 |
oct | 224471266016603 |
9 | 40138314473373 |
10 | 10212540423555 |
11 | 3288128913028 |
12 | 118b31315b403 |
13 | 591066578862 |
14 | 27440a907551 |
15 | 12a9b92d8420 |
hex | 949cad81d83 |
10212540423555 has 8 divisors (see below), whose sum is σ = 16340064677712. Its totient is φ = 5446688225888.
The previous prime is 10212540423511. The next prime is 10212540423563. The reversal of 10212540423555 is 55532404521201.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10212540423555 - 210 = 10212540422531 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 340418014104 + ... + 340418014133.
It is an arithmetic number, because the mean of its divisors is an integer number (2042508084714).
Almost surely, 210212540423555 is an apocalyptic number.
10212540423555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
10212540423555 is a deficient number, since it is larger than the sum of its proper divisors (6127524254157).
10212540423555 is an equidigital number, since it uses as much as digits as its factorization.
10212540423555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 680836028245.
The product of its (nonzero) digits is 240000, while the sum is 39.
Adding to 10212540423555 its reverse (55532404521201), we get a palindrome (65744944944756).
The spelling of 10212540423555 in words is "ten trillion, two hundred twelve billion, five hundred forty million, four hundred twenty-three thousand, five hundred fifty-five".
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