Base | Representation |
---|---|
bin | 1001010010011100110100… |
… | …0110111000111101101111 |
3 | 1100011022110010222202122201 |
4 | 2110213031012320331233 |
5 | 2314310330032214223 |
6 | 33415332125522331 |
7 | 2102556133043626 |
oct | 224471506707557 |
9 | 40138403882581 |
10 | 10212578398063 |
11 | 328814829a918 |
12 | 118b323a133a7 |
13 | 5910713b3492 |
14 | 2744119906bd |
15 | 12a9bc7d9ead |
hex | 949cd1b8f6f |
10212578398063 has 2 divisors, whose sum is σ = 10212578398064. Its totient is φ = 10212578398062.
The previous prime is 10212578398013. The next prime is 10212578398093. The reversal of 10212578398063 is 36089387521201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10212578398063 - 29 = 10212578397551 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10212578397995 and 10212578398013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10212578398013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106289199031 + 5106289199032.
It is an arithmetic number, because the mean of its divisors is an integer number (5106289199032).
Almost surely, 210212578398063 is an apocalyptic number.
10212578398063 is a deficient number, since it is larger than the sum of its proper divisors (1).
10212578398063 is an equidigital number, since it uses as much as digits as its factorization.
10212578398063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4354560, while the sum is 55.
The spelling of 10212578398063 in words is "ten trillion, two hundred twelve billion, five hundred seventy-eight million, three hundred ninety-eight thousand, sixty-three".
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