Base | Representation |
---|---|
bin | 11101101110010100011… |
… | …11100011000000010011 |
3 | 10121122011011201220121211 |
4 | 32313022033203000103 |
5 | 113213110340303243 |
6 | 2101102350200551 |
7 | 133533526335061 |
oct | 16671217430023 |
9 | 3548134656554 |
10 | 1021300322323 |
11 | 364149452366 |
12 | 145b274b3157 |
13 | 75401192068 |
14 | 376072d5031 |
15 | 1b876737d9d |
hex | edca3e3013 |
1021300322323 has 2 divisors, whose sum is σ = 1021300322324. Its totient is φ = 1021300322322.
The previous prime is 1021300322321. The next prime is 1021300322353. The reversal of 1021300322323 is 3232230031201.
1021300322323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1021300322323 - 21 = 1021300322321 is a prime.
Together with 1021300322321, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1021300322294 and 1021300322303.
It is not a weakly prime, because it can be changed into another prime (1021300322321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510650161161 + 510650161162.
It is an arithmetic number, because the mean of its divisors is an integer number (510650161162).
Almost surely, 21021300322323 is an apocalyptic number.
1021300322323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021300322323 is an equidigital number, since it uses as much as digits as its factorization.
1021300322323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 1021300322323 its reverse (3232230031201), we get a palindrome (4253530353524).
The spelling of 1021300322323 in words is "one trillion, twenty-one billion, three hundred million, three hundred twenty-two thousand, three hundred twenty-three".
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