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102130100113 = 1953101420159
BaseRepresentation
bin101111100011101101…
…1011010011110010001
3100202121121210122021111
41133013123122132101
53133130301200423
6114530134253321
710243610345626
oct1370733323621
9322547718244
10102130100113
113a349862918
12179631b7241
139827c09002
144d2bd0434d
1529cb24a60d
hex17c76da791

102130100113 has 8 divisors (see below), whose sum is σ = 109533772800. Its totient is φ = 94929267888.

The previous prime is 102130100087. The next prime is 102130100117. The reversal of 102130100113 is 311001031201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 102130100113 - 217 = 102129969041 is a prime.

It is a super-2 number, since 2×1021301001132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 102130100093 and 102130100102.

It is not an unprimeable number, because it can be changed into a prime (102130100117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50709073 + ... + 50711086.

It is an arithmetic number, because the mean of its divisors is an integer number (13691721600).

Almost surely, 2102130100113 is an apocalyptic number.

It is an amenable number.

102130100113 is a deficient number, since it is larger than the sum of its proper divisors (7403672687).

102130100113 is a wasteful number, since it uses less digits than its factorization.

102130100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 101420231.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 102130100113 its reverse (311001031201), we get a palindrome (413131131314).

The spelling of 102130100113 in words is "one hundred two billion, one hundred thirty million, one hundred thousand, one hundred thirteen".

Divisors: 1 19 53 1007 101420159 1926983021 5375268427 102130100113