Base | Representation |
---|---|
bin | 10111001110001100000101… |
… | …000011000010001011010011 |
3 | 111101121112200002212110211122 |
4 | 113032030011003002023103 |
5 | 101341244432133404021 |
6 | 1001113531543432455 |
7 | 30340441245412235 |
oct | 2716140503021323 |
9 | 441545602773748 |
10 | 102130112013011 |
11 | 2a5a6156783125 |
12 | b5555bba5572b |
13 | 44caa9c840514 |
14 | 1b311a39a8255 |
15 | bc198a389bab |
hex | 5ce3050c22d3 |
102130112013011 has 2 divisors, whose sum is σ = 102130112013012. Its totient is φ = 102130112013010.
The previous prime is 102130112012977. The next prime is 102130112013073. The reversal of 102130112013011 is 110310211031201.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-102130112013011 is a prime.
It is a super-3 number, since 3×1021301120130113 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (102130112013911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51065056006505 + 51065056006506.
It is an arithmetic number, because the mean of its divisors is an integer number (51065056006506).
Almost surely, 2102130112013011 is an apocalyptic number.
102130112013011 is a deficient number, since it is larger than the sum of its proper divisors (1).
102130112013011 is an equidigital number, since it uses as much as digits as its factorization.
102130112013011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 102130112013011 its reverse (110310211031201), we get a palindrome (212440323044212).
The spelling of 102130112013011 in words is "one hundred two trillion, one hundred thirty billion, one hundred twelve million, thirteen thousand, eleven".
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