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10213013000003 = 116115220585693
BaseRepresentation
bin1001010010011110011100…
…0000110000111101000011
31100011100120102202211102212
42110213213000300331003
52314312222312000003
633415443212532335
72102602661101652
oct224474700607503
940140512684385
1010213013000003
113288350649780
12118b4254810ab
1359111044b5a8
142744535a1199
1512a9e5a35dd8
hex949e7030f43

10213013000003 has 8 divisors (see below), whose sum is σ = 11324115756336. Its totient is φ = 9132351415200.

The previous prime is 10213012999963. The next prime is 10213013000051. The reversal of 10213013000003 is 30000031031201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10213013000003 - 214 = 10213012983619 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10213013000803) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7610292176 + ... + 7610293517.

It is an arithmetic number, because the mean of its divisors is an integer number (1415514469542).

Almost surely, 210213013000003 is an apocalyptic number.

10213013000003 is a deficient number, since it is larger than the sum of its proper divisors (1111102756333).

10213013000003 is a wasteful number, since it uses less digits than its factorization.

10213013000003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15220585765.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 10213013000003 its reverse (30000031031201), we get a palindrome (40213044031204).

The spelling of 10213013000003 in words is "ten trillion, two hundred thirteen billion, thirteen million, three", and thus it is an aban number.

Divisors: 1 11 61 671 15220585693 167426442623 928455727273 10213013000003