10213041010433 has 4 divisors (see below), whose sum is σ = 10213051739988. Its totient is φ = 10213030280880.

The previous prime is 10213041010411. The next prime is 10213041010457. The reversal of 10213041010433 is 33401014031201.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 849398170384 + 9363642840049 = 921628^2 + 3060007^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10213041010433 is a prime.

It is a super-2 number, since 2×10213041010433² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10213041010399 and 10213041010408.

It is not an unprimeable number, because it can be changed into a prime (10213041015433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3781166 + ... + 5892647.

It is an arithmetic number, because the mean of its divisors is an integer number (2553262934997).

Almost surely, 2^{10213041010433} is an apocalyptic number.

It is an amenable number.

10213041010433 is a deficient number, since it is larger than the sum of its proper divisors (10729555).

10213041010433 is an equidigital number, since it uses as much as digits as its factorization.

10213041010433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10729554.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 10213041010433 its reverse (33401014031201), we get a palindrome (43614055041634).

The spelling of 10213041010433 in words is "ten trillion, two hundred thirteen billion, forty-one million, ten thousand, four hundred thirty-three".