Base | Representation |
---|---|
bin | 10111001110001101000110… |
… | …100111001110101001101010 |
3 | 111101121122111202201122012110 |
4 | 113032031012213032221222 |
5 | 101341304210234122310 |
6 | 1001114233040423150 |
7 | 30340510433335533 |
oct | 2716150647165152 |
9 | 441548452648173 |
10 | 102131212020330 |
11 | 2a5a66706a2989 |
12 | b555868317ab6 |
13 | 44cac166c461c |
14 | 1b31269b0968a |
15 | bc1a01c22d20 |
hex | 5ce3469cea6a |
102131212020330 has 64 divisors (see below), whose sum is σ = 249390236344320. Its totient is φ = 26760401030976.
The previous prime is 102131212020323. The next prime is 102131212020359. The reversal of 102131212020330 is 33020212131201.
It is a junction number, because it is equal to n+sod(n) for n = 102131212020297 and 102131212020306.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10333282 + ... + 17636301.
It is an arithmetic number, because the mean of its divisors is an integer number (3896722442880).
Almost surely, 2102131212020330 is an apocalyptic number.
102131212020330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
102131212020330 is an abundant number, since it is smaller than the sum of its proper divisors (147259024323990).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
102131212020330 is a wasteful number, since it uses less digits than its factorization.
102131212020330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27971715.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 102131212020330 its reverse (33020212131201), we get a palindrome (135151424151531).
The spelling of 102131212020330 in words is "one hundred two trillion, one hundred thirty-one billion, two hundred twelve million, twenty thousand, three hundred thirty".
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