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10213222121 = 49920467379
BaseRepresentation
bin10011000001100000…
…10110011011101001
3222100202222102212222
421200300112123221
5131404041101441
64405240443425
7511043645534
oct114060263351
928322872788
1010213222121
114371108a43
121b90479575
13c69c23acb
146cc5c7a1b
153eb979d4b
hex260c166e9

10213222121 has 4 divisors (see below), whose sum is σ = 10233690000. Its totient is φ = 10192754244.

The previous prime is 10213222109. The next prime is 10213222157. The reversal of 10213222121 is 12122231201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10213222121 - 210 = 10213221097 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10213222121.

It is not an unprimeable number, because it can be changed into a prime (10213222181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10233191 + ... + 10234188.

It is an arithmetic number, because the mean of its divisors is an integer number (2558422500).

Almost surely, 210213222121 is an apocalyptic number.

It is an amenable number.

10213222121 is a deficient number, since it is larger than the sum of its proper divisors (20467879).

10213222121 is an equidigital number, since it uses as much as digits as its factorization.

10213222121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20467878.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 10213222121 its reverse (12122231201), we get a palindrome (22335453322).

The spelling of 10213222121 in words is "ten billion, two hundred thirteen million, two hundred twenty-two thousand, one hundred twenty-one".

Divisors: 1 499 20467379 10213222121