Base | Representation |
---|---|
bin | 1001010010011111010000… |
… | …0001010000010000001011 |
3 | 1100011101010122102011110211 |
4 | 2110213310001100100023 |
5 | 2314313144143411021 |
6 | 33415521010221551 |
7 | 2102611251042613 |
oct | 224476401202013 |
9 | 40141118364424 |
10 | 10213231232011 |
11 | 3288452854705 |
12 | 118b4865848b7 |
13 | 59114671a362 |
14 | 27447456ba43 |
15 | 12aa09c923e1 |
hex | 949f405040b |
10213231232011 has 2 divisors, whose sum is σ = 10213231232012. Its totient is φ = 10213231232010.
The previous prime is 10213231231999. The next prime is 10213231232033. The reversal of 10213231232011 is 11023213231201.
It is an a-pointer prime, because the next prime (10213231232033) can be obtained adding 10213231232011 to its sum of digits (22).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10213231232011 - 243 = 1417138209803 is a prime.
It is a super-2 number, since 2×102132312320112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10213231233011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106615616005 + 5106615616006.
It is an arithmetic number, because the mean of its divisors is an integer number (5106615616006).
Almost surely, 210213231232011 is an apocalyptic number.
10213231232011 is a deficient number, since it is larger than the sum of its proper divisors (1).
10213231232011 is an equidigital number, since it uses as much as digits as its factorization.
10213231232011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 10213231232011 its reverse (11023213231201), we get a palindrome (21236444463212).
The spelling of 10213231232011 in words is "ten trillion, two hundred thirteen billion, two hundred thirty-one million, two hundred thirty-two thousand, eleven".
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