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102133000253 is a prime number
BaseRepresentation
bin101111100011110011…
…0011110100000111101
3100202121211020222112002
41133013212132200331
53133132022002003
6114530320352045
710243644115064
oct1370746364075
9322554228462
10102133000253
113a350463829
1217964175625
1398286b307b
144d2c45b1db
1529cb61ea88
hex17c799e83d

102133000253 has 2 divisors, whose sum is σ = 102133000254. Its totient is φ = 102133000252.

The previous prime is 102133000223. The next prime is 102133000297. The reversal of 102133000253 is 352000331201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 79085813284 + 23047186969 = 281222^2 + 151813^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-102133000253 is a prime.

It is a super-2 number, since 2×1021330002532 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102133000223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51066500126 + 51066500127.

It is an arithmetic number, because the mean of its divisors is an integer number (51066500127).

Almost surely, 2102133000253 is an apocalyptic number.

It is an amenable number.

102133000253 is a deficient number, since it is larger than the sum of its proper divisors (1).

102133000253 is an equidigital number, since it uses as much as digits as its factorization.

102133000253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 20.

Adding to 102133000253 its reverse (352000331201), we get a palindrome (454133331454).

The spelling of 102133000253 in words is "one hundred two billion, one hundred thirty-three million, two hundred fifty-three", and thus it is an aban number.