Base | Representation |
---|---|
bin | 11101101110011000001… |
… | …01000010101111000111 |
3 | 10121122020022200202101221 |
4 | 32313030011002233013 |
5 | 113213141231420033 |
6 | 2101105410301211 |
7 | 133534352210302 |
oct | 16671405025707 |
9 | 3548208622357 |
10 | 1021331123143 |
11 | 36416487a491 |
12 | 145b35887807 |
13 | 754076876b6 |
14 | 3760b431b39 |
15 | 1b8792be12d |
hex | edcc142bc7 |
1021331123143 has 2 divisors, whose sum is σ = 1021331123144. Its totient is φ = 1021331123142.
The previous prime is 1021331123117. The next prime is 1021331123147. The reversal of 1021331123143 is 3413211331201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1021331123143 - 29 = 1021331122631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1021331123147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510665561571 + 510665561572.
It is an arithmetic number, because the mean of its divisors is an integer number (510665561572).
Almost surely, 21021331123143 is an apocalyptic number.
1021331123143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021331123143 is an equidigital number, since it uses as much as digits as its factorization.
1021331123143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1021331123143 its reverse (3413211331201), we get a palindrome (4434542454344).
The spelling of 1021331123143 in words is "one trillion, twenty-one billion, three hundred thirty-one million, one hundred twenty-three thousand, one hundred forty-three".
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