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10213443011 = 20534974887
BaseRepresentation
bin10011000001100010…
…01100010111000011
3222100210101122220002
421200301030113003
5131404120134021
64405245310215
7511045555532
oct114061142703
928323348802
1010213443011
1143712499a2
121b9056536b
13c69ca0505
146cc644319
153eb9c050b
hex260c4c5c3

10213443011 has 4 divisors (see below), whose sum is σ = 10218419952. Its totient is φ = 10208466072.

The previous prime is 10213443001. The next prime is 10213443017. The reversal of 10213443011 is 11034431201.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11034431201 = 67164693003.

It is a cyclic number.

It is not a de Polignac number, because 10213443011 - 214 = 10213426627 is a prime.

It is a super-2 number, since 2×102134430112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10213443017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2485391 + ... + 2489496.

It is an arithmetic number, because the mean of its divisors is an integer number (2554604988).

Almost surely, 210213443011 is an apocalyptic number.

10213443011 is a deficient number, since it is larger than the sum of its proper divisors (4976941).

10213443011 is an equidigital number, since it uses as much as digits as its factorization.

10213443011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4976940.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 10213443011 its reverse (11034431201), we get a palindrome (21247874212).

The spelling of 10213443011 in words is "ten billion, two hundred thirteen million, four hundred forty-three thousand, eleven".

Divisors: 1 2053 4974887 10213443011