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10213457 is a prime number
BaseRepresentation
bin100110111101…
…100001010001
3201012220020012
4212331201101
510103312312
61002524305
7152545562
oct46754121
921186205
1010213457
115846581
123506695
132167a87
1414dc169
15d6b322
hex9bd851

10213457 has 2 divisors, whose sum is σ = 10213458. Its totient is φ = 10213456.

The previous prime is 10213453. The next prime is 10213501. The reversal of 10213457 is 75431201.

10213457 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10182481 + 30976 = 3191^2 + 176^2 .

It is an emirp because it is prime and its reverse (75431201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10213457 - 22 = 10213453 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10213451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106728 + 5106729.

It is an arithmetic number, because the mean of its divisors is an integer number (5106729).

Almost surely, 210213457 is an apocalyptic number.

It is an amenable number.

10213457 is a deficient number, since it is larger than the sum of its proper divisors (1).

10213457 is an equidigital number, since it uses as much as digits as its factorization.

10213457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 10213457 is about 3195.8499651892. The cubic root of 10213457 is about 216.9656199294.

Adding to 10213457 its reverse (75431201), we get a palindrome (85644658).

The spelling of 10213457 in words is "ten million, two hundred thirteen thousand, four hundred fifty-seven".