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1021421135003 is a prime number
BaseRepresentation
bin11101101110100010111…
…00011010010010011011
310121122110121001211110112
432313101130122102123
5113213332302310003
62101122343434535
7133536524252453
oct16672134322233
93548417054415
101021421135003
11364200669755
12145b5ba55a4b
1375420211b59
1437619382d63
151b88214e3d8
hexedd171a49b

1021421135003 has 2 divisors, whose sum is σ = 1021421135004. Its totient is φ = 1021421135002.

The previous prime is 1021421134967. The next prime is 1021421135027. The reversal of 1021421135003 is 3005311241201.

It is a strong prime.

It is an emirp because it is prime and its reverse (3005311241201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1021421135003 - 230 = 1020347393179 is a prime.

It is a super-2 number, since 2×10214211350032 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1021421135003.

It is not a weakly prime, because it can be changed into another prime (1021421155003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510710567501 + 510710567502.

It is an arithmetic number, because the mean of its divisors is an integer number (510710567502).

Almost surely, 21021421135003 is an apocalyptic number.

1021421135003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1021421135003 is an equidigital number, since it uses as much as digits as its factorization.

1021421135003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 1021421135003 its reverse (3005311241201), we get a palindrome (4026732376204).

The spelling of 1021421135003 in words is "one trillion, twenty-one billion, four hundred twenty-one million, one hundred thirty-five thousand, three".