Base | Representation |
---|---|
bin | 11101101110100010111… |
… | …00011010010010011011 |
3 | 10121122110121001211110112 |
4 | 32313101130122102123 |
5 | 113213332302310003 |
6 | 2101122343434535 |
7 | 133536524252453 |
oct | 16672134322233 |
9 | 3548417054415 |
10 | 1021421135003 |
11 | 364200669755 |
12 | 145b5ba55a4b |
13 | 75420211b59 |
14 | 37619382d63 |
15 | 1b88214e3d8 |
hex | edd171a49b |
1021421135003 has 2 divisors, whose sum is σ = 1021421135004. Its totient is φ = 1021421135002.
The previous prime is 1021421134967. The next prime is 1021421135027. The reversal of 1021421135003 is 3005311241201.
It is a strong prime.
It is an emirp because it is prime and its reverse (3005311241201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1021421135003 - 230 = 1020347393179 is a prime.
It is a super-2 number, since 2×10214211350032 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1021421135003.
It is not a weakly prime, because it can be changed into another prime (1021421155003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510710567501 + 510710567502.
It is an arithmetic number, because the mean of its divisors is an integer number (510710567502).
Almost surely, 21021421135003 is an apocalyptic number.
1021421135003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021421135003 is an equidigital number, since it uses as much as digits as its factorization.
1021421135003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 1021421135003 its reverse (3005311241201), we get a palindrome (4026732376204).
The spelling of 1021421135003 in words is "one trillion, twenty-one billion, four hundred twenty-one million, one hundred thirty-five thousand, three".
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