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102143033113 = 119285730283
BaseRepresentation
bin101111100100000110…
…0101111111100011001
3100202122112010201000111
41133020030233330121
53133142104024423
6114531315404321
710244125312312
oct1371014577431
9322575121014
10102143033113
113a356096650
12179675b36a1
13982a7b6884
144d2d90d609
1529cc45260d
hex17c832ff19

102143033113 has 4 divisors (see below), whose sum is σ = 111428763408. Its totient is φ = 92857302820.

The previous prime is 102143033101. The next prime is 102143033117. The reversal of 102143033113 is 311330341201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-102143033113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (102143033117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4642865131 + ... + 4642865152.

It is an arithmetic number, because the mean of its divisors is an integer number (27857190852).

Almost surely, 2102143033113 is an apocalyptic number.

It is an amenable number.

102143033113 is a deficient number, since it is larger than the sum of its proper divisors (9285730295).

102143033113 is an equidigital number, since it uses as much as digits as its factorization.

102143033113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9285730294.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 102143033113 its reverse (311330341201), we get a palindrome (413473374314).

The spelling of 102143033113 in words is "one hundred two billion, one hundred forty-three million, thirty-three thousand, one hundred thirteen".

Divisors: 1 11 9285730283 102143033113