Base | Representation |
---|---|
bin | 1001010010100110101101… |
… | …0001110010010010110111 |
3 | 1100011120022002022110212210 |
4 | 2110221223101302102313 |
5 | 2314331243401220310 |
6 | 33420451322544503 |
7 | 2103011654541321 |
oct | 224515321622267 |
9 | 40146262273783 |
10 | 10215232054455 |
11 | 328928a20317a |
12 | 118b944668133 |
13 | 5913a50c1b6c |
14 | 2745c419c611 |
15 | 12aac5768820 |
hex | 94a6b4724b7 |
10215232054455 has 16 divisors (see below), whose sum is σ = 16344788107104. Its totient is φ = 5447984822400.
The previous prime is 10215232054387. The next prime is 10215232054543. The reversal of 10215232054455 is 55445023251201.
10215232054455 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10215232054455 - 213 = 10215232046263 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8074584 + ... + 9253613.
It is an arithmetic number, because the mean of its divisors is an integer number (1021549256694).
Almost surely, 210215232054455 is an apocalyptic number.
10215232054455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
10215232054455 is a deficient number, since it is larger than the sum of its proper divisors (6129556052649).
10215232054455 is a wasteful number, since it uses less digits than its factorization.
10215232054455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17367506.
The product of its (nonzero) digits is 240000, while the sum is 39.
The spelling of 10215232054455 in words is "ten trillion, two hundred fifteen billion, two hundred thirty-two million, fifty-four thousand, four hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •