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1022013123133 = 1439710224547
BaseRepresentation
bin11101101111101001011…
…10101010101000111101
310121200222211222221111211
432313310232222220331
5113221040324420013
62101301212044421
7133560303132412
oct16676456525075
93550884887454
101022013123133
11364484845142
121460a6163711
13754b5a63aa2
1437673c42109
151b8b90d823d
hexedf4baaa3d

1022013123133 has 4 divisors (see below), whose sum is σ = 1022723349120. Its totient is φ = 1021302897148.

The previous prime is 1022013123067. The next prime is 1022013123203. The reversal of 1022013123133 is 3313213102201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1022013123133 - 233 = 1013423188541 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1022013121133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355110835 + ... + 355113712.

It is an arithmetic number, because the mean of its divisors is an integer number (255680837280).

Almost surely, 21022013123133 is an apocalyptic number.

It is an amenable number.

1022013123133 is a deficient number, since it is larger than the sum of its proper divisors (710225987).

1022013123133 is an equidigital number, since it uses as much as digits as its factorization.

1022013123133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 710225986.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 1022013123133 its reverse (3313213102201), we get a palindrome (4335226225334).

The spelling of 1022013123133 in words is "one trillion, twenty-two billion, thirteen million, one hundred twenty-three thousand, one hundred thirty-three".

Divisors: 1 1439 710224547 1022013123133