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10220133333 = 33406711111
BaseRepresentation
bin10011000010010101…
…01101101111010101
3222101020222120021210
421201022231233111
5131412323231313
64410044532033
7511156462044
oct114112555725
928336876253
1010220133333
114374aa9493
121b92851019
13c6b4a3797
146cd4a655b
153ec3929c3
hex2612adbd5

10220133333 has 4 divisors (see below), whose sum is σ = 13626844448. Its totient is φ = 6813422220.

The previous prime is 10220133323. The next prime is 10220133337. The reversal of 10220133333 is 33333102201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10220133333 - 210 = 10220132309 is a prime.

It is a super-2 number, since 2×102201333332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10220133337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1703355553 + ... + 1703355558.

It is an arithmetic number, because the mean of its divisors is an integer number (3406711112).

Almost surely, 210220133333 is an apocalyptic number.

It is an amenable number.

10220133333 is a deficient number, since it is larger than the sum of its proper divisors (3406711115).

10220133333 is an equidigital number, since it uses as much as digits as its factorization.

10220133333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3406711114.

The product of its (nonzero) digits is 972, while the sum is 21.

Adding to 10220133333 its reverse (33333102201), we get a palindrome (43553235534).

The spelling of 10220133333 in words is "ten billion, two hundred twenty million, one hundred thirty-three thousand, three hundred thirty-three".

Divisors: 1 3 3406711111 10220133333