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1022013403 = 1223835661
BaseRepresentation
bin111100111010101…
…010111111011011
32122020002122211021
4330322222333123
54043113412103
6245225143311
734216653625
oct7472527733
92566078737
101022013403
11484999884
1224632ab37
13133976b78
1499a3bc15
155eacdbbd
hex3ceaafdb

1022013403 has 4 divisors (see below), whose sum is σ = 1022850288. Its totient is φ = 1021176520.

The previous prime is 1022013397. The next prime is 1022013407. The reversal of 1022013403 is 3043102201.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1022013403 - 29 = 1022012891 is a prime.

It is a super-2 number, since 2×10220134032 = 2089022791823280818, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1022013407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 416608 + ... + 419053.

It is an arithmetic number, because the mean of its divisors is an integer number (255712572).

Almost surely, 21022013403 is an apocalyptic number.

1022013403 is a deficient number, since it is larger than the sum of its proper divisors (836885).

1022013403 is an equidigital number, since it uses as much as digits as its factorization.

1022013403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 836884.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 1022013403 is about 31968.9443522929. The cubic root of 1022013403 is about 1007.2846066522.

Adding to 1022013403 its reverse (3043102201), we get a palindrome (4065115604).

The spelling of 1022013403 in words is "one billion, twenty-two million, thirteen thousand, four hundred three".

Divisors: 1 1223 835661 1022013403