Base | Representation |
---|---|
bin | 1001010010111101010110… |
… | …1000010100000111011011 |
3 | 1100012010222202111202221111 |
4 | 2110233111220110013123 |
5 | 2314431221143443342 |
6 | 33423334450321151 |
7 | 2103315423432262 |
oct | 224572550240733 |
9 | 40163882452844 |
10 | 10221311312347 |
11 | 3290919848653 |
12 | 1190b605891b7 |
13 | 591b3371b295 |
14 | 2749dd71d5d9 |
15 | 12ad2e30a217 |
hex | 94bd5a141db |
10221311312347 has 2 divisors, whose sum is σ = 10221311312348. Its totient is φ = 10221311312346.
The previous prime is 10221311312321. The next prime is 10221311312357. The reversal of 10221311312347 is 74321311312201.
It is a happy number.
10221311312347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10221311312347 - 215 = 10221311279579 is a prime.
It is not a weakly prime, because it can be changed into another prime (10221311312357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5110655656173 + 5110655656174.
It is an arithmetic number, because the mean of its divisors is an integer number (5110655656174).
Almost surely, 210221311312347 is an apocalyptic number.
10221311312347 is a deficient number, since it is larger than the sum of its proper divisors (1).
10221311312347 is an equidigital number, since it uses as much as digits as its factorization.
10221311312347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 10221311312347 its reverse (74321311312201), we get a palindrome (84542622624548).
The spelling of 10221311312347 in words is "ten trillion, two hundred twenty-one billion, three hundred eleven million, three hundred twelve thousand, three hundred forty-seven".
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