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1022133000113 is a prime number
BaseRepresentation
bin11101101111110111101…
…11111101011110110001
310121201022012120022210222
432313323313331132301
5113221312022000423
62101321133302425
7133563260102111
oct16677367753661
93551265508728
101022133000113
11364536482525
1214611a334a15
1375504846a04
1437685b29041
151b8c48b73c8
hexedfbdfd7b1

1022133000113 has 2 divisors, whose sum is σ = 1022133000114. Its totient is φ = 1022133000112.

The previous prime is 1022133000101. The next prime is 1022133000131. The reversal of 1022133000113 is 3110003312201.

Together with next prime (1022133000131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 937511935504 + 84621064609 = 968252^2 + 290897^2 .

It is a cyclic number.

It is not a de Polignac number, because 1022133000113 - 232 = 1017838032817 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1022133000091 and 1022133000100.

It is not a weakly prime, because it can be changed into another prime (1022133000173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 511066500056 + 511066500057.

It is an arithmetic number, because the mean of its divisors is an integer number (511066500057).

Almost surely, 21022133000113 is an apocalyptic number.

It is an amenable number.

1022133000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1022133000113 is an equidigital number, since it uses as much as digits as its factorization.

1022133000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1022133000113 its reverse (3110003312201), we get a palindrome (4132136312314).

The spelling of 1022133000113 in words is "one trillion, twenty-two billion, one hundred thirty-three million, one hundred thirteen", and thus it is an aban number.