Base | Representation |
---|---|
bin | 10011000010100011… |
… | …11101000100001001 |
3 | 222101101112222112221 |
4 | 21201101331010021 |
5 | 131413314443423 |
6 | 4410153334041 |
7 | 511211554660 |
oct | 114121750411 |
9 | 28341488487 |
10 | 10222031113 |
11 | 43760852a8 |
12 | 1b93407321 |
13 | c6b9b9528 |
14 | 6cd83bdd7 |
15 | 3ec619e5d |
hex | 26147d109 |
10222031113 has 4 divisors (see below), whose sum is σ = 11682321280. Its totient is φ = 8761740948.
The previous prime is 10222031111. The next prime is 10222031119. The reversal of 10222031113 is 31113022201.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31113022201 = 397 ⋅78370333.
It is a cyclic number.
It is not a de Polignac number, because 10222031113 - 21 = 10222031111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (10222031111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 730145073 + ... + 730145086.
It is an arithmetic number, because the mean of its divisors is an integer number (2920580320).
Almost surely, 210222031113 is an apocalyptic number.
It is an amenable number.
10222031113 is a deficient number, since it is larger than the sum of its proper divisors (1460290167).
10222031113 is an equidigital number, since it uses as much as digits as its factorization.
10222031113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1460290166.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 10222031113 its reverse (31113022201), we get a palindrome (41335053314).
The spelling of 10222031113 in words is "ten billion, two hundred twenty-two million, thirty-one thousand, one hundred thirteen".
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