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102220584331199 is a prime number
BaseRepresentation
bin10111001111100000010101…
…100111100010011110111111
3111101221012012021111102201012
4113033200111213202132333
5101344240224042044244
61001223253235305435
730350123241420605
oct2717402547423677
9441835167442635
10102220584331199
112a630562a73924
12b56b04aa4b27b
13450648a474ac9
141b357074d3875
15bc3ed2e1289e
hex5cf8159e27bf

102220584331199 has 2 divisors, whose sum is σ = 102220584331200. Its totient is φ = 102220584331198.

The previous prime is 102220584331183. The next prime is 102220584331277. The reversal of 102220584331199 is 991133485022201.

It is a weak prime.

It is an emirp because it is prime and its reverse (991133485022201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102220584331199 - 24 = 102220584331183 is a prime.

It is a super-3 number, since 3×1022205843311993 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102220584339199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51110292165599 + 51110292165600.

It is an arithmetic number, because the mean of its divisors is an integer number (51110292165600).

Almost surely, 2102220584331199 is an apocalyptic number.

102220584331199 is a deficient number, since it is larger than the sum of its proper divisors (1).

102220584331199 is an equidigital number, since it uses as much as digits as its factorization.

102220584331199 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 933120, while the sum is 50.

The spelling of 102220584331199 in words is "one hundred two trillion, two hundred twenty billion, five hundred eighty-four million, three hundred thirty-one thousand, one hundred ninety-nine".