Base | Representation |
---|---|
bin | 10011000010100100… |
… | …01011001110101011 |
3 | 222101101122221010202 |
4 | 21201102023032223 |
5 | 131413323323011 |
6 | 4410154502415 |
7 | 511212216062 |
oct | 114122131653 |
9 | 28341587122 |
10 | 10222089131 |
11 | 4376114951 |
12 | 1b93434a0b |
13 | c6ba09a67 |
14 | 6cd8551d9 |
15 | 3ec62c23b |
hex | 26148b3ab |
10222089131 has 2 divisors, whose sum is σ = 10222089132. Its totient is φ = 10222089130.
The previous prime is 10222089121. The next prime is 10222089133. The reversal of 10222089131 is 13198022201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10222089131 - 26 = 10222089067 is a prime.
It is a super-2 number, since 2×102220891312 (a number of 21 digits) contains 22 as substring.
Together with 10222089133, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 10222089094 and 10222089103.
It is not a weakly prime, because it can be changed into another prime (10222089133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5111044565 + 5111044566.
It is an arithmetic number, because the mean of its divisors is an integer number (5111044566).
Almost surely, 210222089131 is an apocalyptic number.
10222089131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10222089131 is an equidigital number, since it uses as much as digits as its factorization.
10222089131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 29.
The spelling of 10222089131 in words is "ten billion, two hundred twenty-two million, eighty-nine thousand, one hundred thirty-one".
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