Base | Representation |
---|---|
bin | 11101110000001101001… |
… | …10101000000111101001 |
3 | 10121201202202021112211211 |
4 | 32320012212220013221 |
5 | 113222144112134140 |
6 | 2101351043353121 |
7 | 133600604112226 |
oct | 16700646500751 |
9 | 3551682245754 |
10 | 1022313005545 |
11 | 364619049247 |
12 | 14616a6827a1 |
13 | 75532c201c0 |
14 | 376a19c494d |
15 | 1b8d55c22ea |
hex | ee069a81e9 |
1022313005545 has 32 divisors (see below), whose sum is σ = 1367913002400. Its totient is φ = 728259323904.
The previous prime is 1022313005471. The next prime is 1022313005551. The reversal of 1022313005545 is 5455003132201.
It can be written as a sum of positive squares in 16 ways, for example, as 520614199296 + 501698806249 = 721536^2 + 708307^2 .
It is a cyclic number.
It is not a de Polignac number, because 1022313005545 - 29 = 1022313005033 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1887979 + ... + 2368351.
It is an arithmetic number, because the mean of its divisors is an integer number (42747281325).
Almost surely, 21022313005545 is an apocalyptic number.
It is an amenable number.
1022313005545 is a deficient number, since it is larger than the sum of its proper divisors (345599996855).
1022313005545 is a wasteful number, since it uses less digits than its factorization.
1022313005545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 481549.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 1022313005545 its reverse (5455003132201), we get a palindrome (6477316137746).
The spelling of 1022313005545 in words is "one trillion, twenty-two billion, three hundred thirteen million, five thousand, five hundred forty-five".
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