Base | Representation |
---|---|
bin | 10111001111101011001010… |
… | …101000111101110110011111 |
3 | 111101222022012120201110120121 |
4 | 113033223022220331312133 |
5 | 101344433032044104002 |
6 | 1001232455102055411 |
7 | 30351014333233054 |
oct | 2717531250756637 |
9 | 441868176643517 |
10 | 102232211316127 |
11 | 2a63548a110782 |
12 | b57135487a567 |
13 | 45075c1255849 |
14 | 1b360cb77302b |
15 | bc4463a50237 |
hex | 5cfacaa3dd9f |
102232211316127 has 2 divisors, whose sum is σ = 102232211316128. Its totient is φ = 102232211316126.
The previous prime is 102232211316097. The next prime is 102232211316269. The reversal of 102232211316127 is 721613112232201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 102232211316127 - 27 = 102232211315999 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 102232211316092 and 102232211316101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102232211316427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51116105658063 + 51116105658064.
It is an arithmetic number, because the mean of its divisors is an integer number (51116105658064).
Almost surely, 2102232211316127 is an apocalyptic number.
102232211316127 is a deficient number, since it is larger than the sum of its proper divisors (1).
102232211316127 is an equidigital number, since it uses as much as digits as its factorization.
102232211316127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 34.
Adding to 102232211316127 its reverse (721613112232201), we get a palindrome (823845323548328).
The spelling of 102232211316127 in words is "one hundred two trillion, two hundred thirty-two billion, two hundred eleven million, three hundred sixteen thousand, one hundred twenty-seven".
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