Base | Representation |
---|---|
bin | 1001010011000100100011… |
… | …0110001110101110100011 |
3 | 1100012022222110211202120010 |
4 | 2110301020312032232203 |
5 | 2314444201022341011 |
6 | 33424254342020003 |
7 | 2103414345050634 |
oct | 224611066165643 |
9 | 40168873752503 |
10 | 10223244340131 |
11 | 3291720a01a79 |
12 | 11913bba17603 |
13 | 592081046cc4 |
14 | 274b4434388b |
15 | 12ade3d8e1a6 |
hex | 94c48d8eba3 |
10223244340131 has 4 divisors (see below), whose sum is σ = 13630992453512. Its totient is φ = 6815496226752.
The previous prime is 10223244340121. The next prime is 10223244340151. The reversal of 10223244340131 is 13104344232201.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 10223244340131 - 29 = 10223244339619 is a prime.
It is a super-2 number, since 2×102232443401312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10223244340121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1703874056686 + ... + 1703874056691.
It is an arithmetic number, because the mean of its divisors is an integer number (3407748113378).
Almost surely, 210223244340131 is an apocalyptic number.
10223244340131 is a deficient number, since it is larger than the sum of its proper divisors (3407748113381).
10223244340131 is an equidigital number, since it uses as much as digits as its factorization.
10223244340131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3407748113380.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 10223244340131 its reverse (13104344232201), we get a palindrome (23327588572332).
The spelling of 10223244340131 in words is "ten trillion, two hundred twenty-three billion, two hundred forty-four million, three hundred forty thousand, one hundred thirty-one".
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