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10230120137 is a prime number
BaseRepresentation
bin10011000011100001…
…10011111011001001
3222101221202221121102
421201300303323021
5131422402321022
64411042551145
7511340405066
oct114160637311
928357687542
1010230120137
11437a6aa746
121b960684b5
13c7058c333
146d0945c6d
153ed1b6a92
hex261c33ec9

10230120137 has 2 divisors, whose sum is σ = 10230120138. Its totient is φ = 10230120136.

The previous prime is 10230120101. The next prime is 10230120151. The reversal of 10230120137 is 73102103201.

10230120137 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5486216761 + 4743903376 = 74069^2 + 68876^2 .

It is an emirp because it is prime and its reverse (73102103201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10230120137 - 212 = 10230116041 is a prime.

It is not a weakly prime, because it can be changed into another prime (10230120167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5115060068 + 5115060069.

It is an arithmetic number, because the mean of its divisors is an integer number (5115060069).

Almost surely, 210230120137 is an apocalyptic number.

It is an amenable number.

10230120137 is a deficient number, since it is larger than the sum of its proper divisors (1).

10230120137 is an equidigital number, since it uses as much as digits as its factorization.

10230120137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 20.

Adding to 10230120137 its reverse (73102103201), we get a palindrome (83332223338).

The spelling of 10230120137 in words is "ten billion, two hundred thirty million, one hundred twenty thousand, one hundred thirty-seven".